If z is a multiple of 7899, what is the remainder when z^2 is divided by 9?
If z is a multiple of 7899, what is the remainder when z^2 is divided by 9?
Answer/Solution
0
Steps/Work
The sum of the digits is 7+8+9+9=33.
Thus 3 is a factor of 7899, so 3 is a factor of z.
Then 3^3 = 9 is a factor of z^2.
Then the remainder when z^2 is divided by 9 is 0.
The answer is A.
Thus 3 is a factor of 7899, so 3 is a factor of z.
Then 3^3 = 9 is a factor of z^2.
Then the remainder when z^2 is divided by 9 is 0.
The answer is A.