54 is to be divided into two parts such that the sum of 10 times the first and 22 times the second ...

54 is to be divided into two parts such that the sum of 10 times the first and 22 times the second is 780. The bigger part is

Answer/Solution

34

Steps/Work

Solution
Let the two parts be (54 - x) and x.
Then, 10(54-x)+22x=780
= 12x = 240
‹=›x = 20.
Therefore Bigger part = (54-x) = 34.
Answer D

General Calculator / Auto Solver

is to be divided into two parts such that the sum of times the first and times the second is . The bigger part is

Calculated Answer

34

Step by Step Solution

In order to solve problem, you must evaluate n₀ - (n₃ - n₀ * n₁) / (n₂ - n₁).

n₀ =	54
n₁ =	10
n₂ =	22
n₃ =	780

n₀ - (n₃ - n₀ * n₁) / (n₂ - n₁)
Evaluate n₀ * n₁ = 540
n₀ - (n₃ - 540) / (n₂ - n₁)
Evaluate n₃ - 540 = 240
n₀ - 240 / (n₂ - n₁)
Evaluate n₂ - n₁ = 12
n₀ - 240 / 12
Evaluate 240 / 12 = 20
n₀ - 20
Evaluate n₀ - 20 = 34
34
The answer to the problem and the result of n₀ - (n₃ - n₀ * n₁) / (n₂ - n₁) is 34