Pipe A fills a tank of capacity 950 liters at the rate of 40 liters a minute.

Pipe A fills a tank of capacity 950 liters at the rate of 40 liters a minute. Another pipe B fills the same tank at the rate of 30 liters a minute. A pipe at the bottom of the tank drains the tank at the rate of 20 liters a minute. If pipe A is kept open for a minute and then closed and pipe B is open for a minute and then closed and then pipe C is open for a minute and then closed and the cycle is repeated, when will the tank be full?

Quiz

Answer/Solution

57 minutes

Steps/Work

In one cycle they fill 40+30-20 = 50 liters
950 = 50*n => n = 19
here n = number of cycles.
total time = 19*3 = 57 as in one cycle there are 3 minutes.
thus 57 minutes
ANSWER:A

Physics Calculator / Auto Solver

Pipe a fills a tank of capacity liters at the rate of liters a minute. Another pipe b fills the same tank at the rate of liters a minute. A pipe at the bottom of the tank drains the tank at the rate of liters a minute. If pipe a is kept open for a minute and then closed and pipe b is open for a minute and then closed and then pipe c is open for a minute and then closed and the cycle is repeated, when will the tank be full?

Calculated Answer

57

Step by Step Solution

In order to solve problem, you must evaluate n0 / (n1 + n2 - n3) * 3.

n0 =950
n1 =40
n2 =30
n3 =20