What is the smallest integer X such that 2X+2 is divisible by 33, 44, 55, and 666?
What is the smallest integer X such that 2X+2 is divisible by 33, 44, 55, and 666?
Answer/Solution
X = 36629
Steps/Work
33 = 3 * 11
44 = 2 * 2 * 11
55 = 5 * 11
666 = 2 * 3 * 3 * 37
So 2X+2 = 2 * 2 * 3 * 3 * 5 * 11 * 37 = 73260, and X = (73260 - 2)/2 = 36629, which is option D.
44 = 2 * 2 * 11
55 = 5 * 11
666 = 2 * 3 * 3 * 37
So 2X+2 = 2 * 2 * 3 * 3 * 5 * 11 * 37 = 73260, and X = (73260 - 2)/2 = 36629, which is option D.