If a car went the first third of the distance at 80 kmh, the second third at 15 kmh, and the last ...
If a car went the first third of the distance at 80 kmh, the second third at 15 kmh, and the last third at 48 kmh, what was the average speed of the car for the entire trip?
Answer/Solution
30 kmh
Steps/Work
Assume D/3 = 240 (this number is convenient because it is divisible by 80, 15 and 48)
So:
240 = 80*T1 = 3 hrs
240 = 15*T2 = 16 hrs
240 = 48*T3 = 5 hrs
T = T1 + T2 + T3 = 24 hrs
D = RT
(240*3) = R*24
R = 30
ANSWER: A
So:
240 = 80*T1 = 3 hrs
240 = 15*T2 = 16 hrs
240 = 48*T3 = 5 hrs
T = T1 + T2 + T3 = 24 hrs
D = RT
(240*3) = R*24
R = 30
ANSWER: A