A rope of which a calf is tied is increased from 12 m to 21 m, how much additional grassy ground ...

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A rope of which a calf is tied is increased from m to m, how much additional grassy ground shall it graze?

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Calculated Answer

933.42857142857

Step by Step Solution

In order to solve problem, you must evaluate (10 * 2 + 2) / (3 + 4) * (n₁^2 - n₀^2).

• (10 * 2 + 2) / (3 + 4) * (n₁^2 - n₀^2)

• Evaluate 10 * 2 = 20

  (20 + 2) / (3 + 4) * (n₁^2 - n₀^2)

• Evaluate 20 + 2 = 22

  22 / (3 + 4) * (n₁^2 - n₀^2)

• Evaluate 3 + 4 = 7

  22 / 7 * (n₁^2 - n₀^2)

• Evaluate 22 / 7 = 3.1428571428571

  3.1428571428571 * (n₁^2 - n₀^2)

• Evaluate n₁^2 = 441

  3.1428571428571 * (441 - n₀^2)

• Evaluate n₀^2 = 144

  3.1428571428571 * (441 - 144)

• Evaluate 441 - 144 = 297

  3.1428571428571 * 297

• Evaluate 3.1428571428571 * 297 = 933.42857142857

  933.42857142857
• The answer to the problem and the result of (10 * 2 + 2) / (3 + 4) * (n₁^2 - n₀^2) is 933.42857142857