Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each....

Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability E that Jane will be on the same committee as Albert?

Quiz

Answer/Solution

40%

Steps/Work

Total number of ways to choose 3 member committee - 6C3=(6!/3!3!)=20
No. of ways Albert n Jane are in same committee:- (4C1 * 2)= 8
Probability E= (8/20) *100 =40%.
+1 for me.. :D

Probability Calculator / Auto Solver

Two mba admissions committees are to be formed randomly from second year mbas with members each. What is the probability e that jane will be on the same committee as albert?

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