The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75.
The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?
Answer/Solution
Rs. 16, Rs. 10
Steps/Work
Solution:
Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
=> The cost of 2 books = Rs. 26
Let the price of each book be x and y.
=> x + y = 26 ---------------- (1)
(160/100)y+y =26
On Solving for y, we get
y = 10.
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
x = 16.
So the price of each book is Rs. 16 and Rs. 10 respectively.
Answer: Option C
Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
=> The cost of 2 books = Rs. 26
Let the price of each book be x and y.
=> x + y = 26 ---------------- (1)
(160/100)y+y =26
On Solving for y, we get
y = 10.
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
x = 16.
So the price of each book is Rs. 16 and Rs. 10 respectively.
Answer: Option C