A restaurant orders 150 kg of pumpkins from the farmer’s market.
A restaurant orders 150 kg of pumpkins from the farmer’s market. The farmer fills the order with 23 pumpkins. The average mass of the first 20 pumpkins is 6.5 kg. What must be the minimum average mass of the remaining 3 pumpkins to fill the order?
Answer/Solution
6.67 kg
Steps/Work
The order of 150 kg is distributed among 23 pumpkins.
20 of the pumpkins weigh a total of 20*6,5=130.
The remaining 3 pumpkins weigh a total of 150-130=20.
The average of the 3 remaining pumpkins(answer to the question) is 20/3=6,666... or 6,67.
Answer: C.
20 of the pumpkins weigh a total of 20*6,5=130.
The remaining 3 pumpkins weigh a total of 150-130=20.
The average of the 3 remaining pumpkins(answer to the question) is 20/3=6,666... or 6,67.
Answer: C.