A bakery currently has 7 pies and 4 cakes in its inventory.
A bakery currently has 7 pies and 4 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?
Answer/Solution
5/11
Steps/Work
The total number of ways to choose 5 from 11 is 11C5 = 462.
The number of ways that include 3 pies is 7C3*4C2 = 35*6 = 210
P(exactly 3 pies) = 210/462 = 5/11
The answer is B.
The number of ways that include 3 pies is 7C3*4C2 = 35*6 = 210
P(exactly 3 pies) = 210/462 = 5/11
The answer is B.