There are 408 boys and 264 girls in a school which are to be divided into equal sections of either ...

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There are boys and girls in a school which are to be divided into equal sections of either boys or girls alone. Find the total number of sections thus formed.

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Calculated Answer

28

Step by Step Solution

In order to solve problem, you must evaluate (n₀ + n₁) / (2 * 2 * 2 * 3).

• (n₀ + n₁) / (2 * 2 * 2 * 3)

• Evaluate n₀ + n₁ = 672

  672 / (2 * 2 * 2 * 3)

• Evaluate 2 * 2 = 4

  672 / (4 * 2 * 3)

• Evaluate 4 * 2 = 8

  672 / (8 * 3)

• Evaluate 8 * 3 = 24

  672 / 24

• Evaluate 672 / 24 = 28

  28
• The answer to the problem and the result of (n₀ + n₁) / (2 * 2 * 2 * 3) is 28