Donovan and Michael are racing around a circular 400-meter track.
Donovan and Michael are racing around a circular 400-meter track. If Donovan runs each lap in 45 seconds and Michael runs each lap in 36 seconds, how many laps will Michael have to complete in order to pass Donovan, assuming they start at the same time?
Answer/Solution
5
Steps/Work
One way of approaching this question is by Relative speed method
1. Speed/ Rate of Donovan = Distance/ time => 400/45 =>80/9
2. Speed/ Rate of Michael = Distance/ time => 400/36 => 100/9
Relative Speed between them = 100/9 - 80/9 => 20/9 (We subtract the Rates if moving in the same direction and add the rates if moving in the opposite direction)
In order to pass Donovan-
Distance to be covered = 400, Relative Rate = 20/9
Total Time taken by Micheal to surpass Donovan = Distance / rate => 400*9/20 => 3600/10 => 180
No. of laps taken by Michael = Total time / Michael's rate => 180/36 => 5
Hence correct answer is 5 Laps.
D
1. Speed/ Rate of Donovan = Distance/ time => 400/45 =>80/9
2. Speed/ Rate of Michael = Distance/ time => 400/36 => 100/9
Relative Speed between them = 100/9 - 80/9 => 20/9 (We subtract the Rates if moving in the same direction and add the rates if moving in the opposite direction)
In order to pass Donovan-
Distance to be covered = 400, Relative Rate = 20/9
Total Time taken by Micheal to surpass Donovan = Distance / rate => 400*9/20 => 3600/10 => 180
No. of laps taken by Michael = Total time / Michael's rate => 180/36 => 5
Hence correct answer is 5 Laps.
D