Mixture A is 40 percent alcohol, and mixture B is 80 percent alcohol.
Mixture A is 40 percent alcohol, and mixture B is 80 percent alcohol. If the two are poured together to create a 4-gallon mixture that contains 50 percent alcohol, approximately how many gallons of mixture A are in the mixture?
Answer/Solution
2.4
Steps/Work
(80-50)/(50-40) = Qa/Qb
30/10 = Qa/Qb
3/1 = Qa/Qb
Qa = (3/5) * 4 = 12/5 = 2.4 approx
Answer : E
30/10 = Qa/Qb
3/1 = Qa/Qb
Qa = (3/5) * 4 = 12/5 = 2.4 approx
Answer : E