A runs 1 2⁄3 times as fast as B.
A runs 1 2⁄3 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
Answer/Solution
200 m
Steps/Work
Speed of A : Speed of B = 5⁄3 : 1 = 5 : 3
i.e., In a race of 5 m, A runs 5 m and B runs 3 m
i.e., A gains 2 m over B in a race of 5 m
=> A gains 80 m over B in a race of 52×80 = 200 m
Hence, winning point should be 200 m away from the starting point.
ANSWER:A
i.e., In a race of 5 m, A runs 5 m and B runs 3 m
i.e., A gains 2 m over B in a race of 5 m
=> A gains 80 m over B in a race of 52×80 = 200 m
Hence, winning point should be 200 m away from the starting point.
ANSWER:A