Let p be a prime number. If N = 8p, how many distinct even divisors does N have?
Let p be a prime number. If N = 8p, how many distinct even divisors does N have?
Answer/Solution
2
Steps/Work
The correct answer is D. There are two: 2 and 2p.
8p = 2*2*2p = (2*2)*2p. Since we care only about distinct divisors, we ignore the fact that 2 appears three times.
8p = 2*2*2p = (2*2)*2p. Since we care only about distinct divisors, we ignore the fact that 2 appears three times.