Xavier, Yvonne, and Zelda each try independently to solve a problem.
Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/3, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?
Answer/Solution
1/16
Steps/Work
P(Xavier will solve)=1/3
P(Yvonne will solve)=1/2
P(Zelda will NOT solve) = 1- 5/8 = 3/8.
Now, we need to multiply all this Ps to find an answer:
p= (1/3)*(1/2)*(3/8) = 1/16.
Ans. A.
P(Yvonne will solve)=1/2
P(Zelda will NOT solve) = 1- 5/8 = 3/8.
Now, we need to multiply all this Ps to find an answer:
p= (1/3)*(1/2)*(3/8) = 1/16.
Ans. A.