There are 8 cars parked in the lot 5 red and 3 blue, James threw two stone at the cars and three of ...
There are 8 cars parked in the lot 5 red and 3 blue, James threw two stone at the cars and three of the cars were hit, what is the probability that a stone did not hit any red car provided each stone hit one different car?.
Answer/Solution
3/28
Steps/Work
Since there were 5 red cars, the subset from which the 2 car hit should be chosen are the 3 blue cars from the universe of 8,
The first car can be one of the 3 from the 8 with probability 3/8.
The second car can be one of the 2 from the 7 remaining with probability 2/7.
The total probability will be 3/8 × 2/7. On cancellation, this comes to 3/28
Thus, the answer is E - 3/28
The first car can be one of the 3 from the 8 with probability 3/8.
The second car can be one of the 2 from the 7 remaining with probability 2/7.
The total probability will be 3/8 × 2/7. On cancellation, this comes to 3/28
Thus, the answer is E - 3/28