For any positive integer n, the sum of the first n positive integers equals n(n+1)/2.
For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum m of all the even integers between 99 and 301?
Answer/Solution
20,200
Steps/Work
I would solve it in a different way.
First of all, total number of even integers between 99 and 301 are, (301-99)/2 = 202/2=101
Average = (301+99)/2 = 400/2 = 200
Sum m= Average*total count = 200*101 = 20,200
Answer is B
First of all, total number of even integers between 99 and 301 are, (301-99)/2 = 202/2=101
Average = (301+99)/2 = 400/2 = 200
Sum m= Average*total count = 200*101 = 20,200
Answer is B