A honey bee flies for 10 seconds, from a daisy to a rose.
A honey bee flies for 10 seconds, from a daisy to a rose. It immediately continues to a poppy, flying for 6 additional seconds. The distance the bee passed, flying from the daisy to the rose is 3 meters longer than the distance it passed flying from the rose to the poppy. The bee flies to the poppy at 3 meters per second faster than her speed flying to the rose. The bee flies how many meters per second from the daisy to the rose?
Answer/Solution
4.2
Steps/Work
Let the speed be 's' and let the distance between rose and poppy be 'x'
The problem boils down to:
Rose to Poppy: s+3=x/6 ------- 1
Daisy to Rose: s=(x+3)/10------ 2
so from 1 we can re write x as x=6s+18
substitute the value of x in 2 gives us s=4.2 m/s
A
The problem boils down to:
Rose to Poppy: s+3=x/6 ------- 1
Daisy to Rose: s=(x+3)/10------ 2
so from 1 we can re write x as x=6s+18
substitute the value of x in 2 gives us s=4.2 m/s
A