A boy is traveling from his house to school at 10km/hr and reached school 2hours late.
A boy is traveling from his house to school at 10km/hr and reached school 2hours late. Next day he traveled 20km/hr and reached 1hour early. Then find the distance between house and school?
Answer/Solution
60km
Steps/Work
Let distance be x
S1 = 10km/hr
S2 = 20km/hr
T1 = x/10hr
T2 = x/20hr
Difference in time = 2+1 = 3hr
(x/10)-(x/20) = 3
x = 60km
Answer is D
S1 = 10km/hr
S2 = 20km/hr
T1 = x/10hr
T2 = x/20hr
Difference in time = 2+1 = 3hr
(x/10)-(x/20) = 3
x = 60km
Answer is D