If the sum of two numbers is 45 and the L.C.M and sum of the reciprocal of the numbers are 120 and ...
If the sum of two numbers is 45 and the L.C.M and sum of the reciprocal of the numbers are 120 and 11/120 then HCF of numbers is equal to:
Answer/Solution
5
Steps/Work
Let the numbers be a and b and HCF is x,
Then, a + b = 45 and ab = x * 120 = 120x
Required sum = 1/a + 1/b = (a + b)/ab = 45/120x = 11/120.
x=5.
ANSWER:B
Then, a + b = 45 and ab = x * 120 = 120x
Required sum = 1/a + 1/b = (a + b)/ab = 45/120x = 11/120.
x=5.
ANSWER:B