A car starts from X and moves towards Y.
A car starts from X and moves towards Y. At the same time another car starts from Y and moves towards X. Both travel at a constant speed and meet after 7 hours. During that time, the faster car traveled 2/3 of the distance XY. How long would it take the slower car to travel the distance XY?
Answer/Solution
21 hours
Steps/Work
If one car travelled 2/3, then the other car must have travelled only 1/3, as they are meeting after 7 hours in a certain point. So:
(1/3)XY= 7*y --> It took the car 7 hours to travel 1/3 of the distance at a constant speed y.
So if we solve this last equation:
XY= 3*7*y= 21*y --> It will take this car 21 hours in total to reach its final destination.
Answer: E
(1/3)XY= 7*y --> It took the car 7 hours to travel 1/3 of the distance at a constant speed y.
So if we solve this last equation:
XY= 3*7*y= 21*y --> It will take this car 21 hours in total to reach its final destination.
Answer: E