Vikas can cover a distance in 1 hr 24 min by covering (left(dfrac{2}{3}right)^{rd})of the distance ...
Vikas can cover a distance in 1 hr 24 min by covering (left(dfrac{2}{3}right)^{rd})of the distance at 4 kmph and the rest at 5kmph. The total distance is?
Answer/Solution
6 km
Steps/Work
Let total distance be SS
total time = 1 hr 24 min = 84 min
= 8460=21158460=2115 hr
Let Vikas travels from A−>T−>SA−>T−>S
A ------------------------ T ------------ S
<---------- (2S3)(2S3)---------><----(S3)(S3)---->
AA to TT :: speed = 4 kmph
Distance = (23)×S(23)×S
T to S :: speed = 5 km =
Distance = (1−23)S=13S(1−23)S=13S
Total time:
2115=2/3S4+1/3S42115=2/3S4+1/3S4
84=10S+4S84=10S+4S {Multiply both sides by 15×415×4}
S=8414=6S=8414=6 km
Option(C) is correct
total time = 1 hr 24 min = 84 min
= 8460=21158460=2115 hr
Let Vikas travels from A−>T−>SA−>T−>S
A ------------------------ T ------------ S
<---------- (2S3)(2S3)---------><----(S3)(S3)---->
AA to TT :: speed = 4 kmph
Distance = (23)×S(23)×S
T to S :: speed = 5 km =
Distance = (1−23)S=13S(1−23)S=13S
Total time:
2115=2/3S4+1/3S42115=2/3S4+1/3S4
84=10S+4S84=10S+4S {Multiply both sides by 15×415×4}
S=8414=6S=8414=6 km
Option(C) is correct