14, 23, 32, 41, 50, 59, … In the sequence above, each term is 9 more than the previous term.
14, 23, 32, 41, 50, 59, …
In the sequence above, each term is 9 more than the previous term. What is the 41st term Y of the sequence?
Answer/Solution
374
Steps/Work
First term , a= 14
Common difference , d = 9
nth term , tn = a + (n-1)d
41st term Y, t41 = a+ 40*d = 14 + 40*9 = 374
Answer D
Common difference , d = 9
nth term , tn = a + (n-1)d
41st term Y, t41 = a+ 40*d = 14 + 40*9 = 374
Answer D