Tickets numbered from 1 to 24 are mixed and then a ticket is selected randomly.
Tickets numbered from 1 to 24 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3?
Answer/Solution
1/3
Steps/Work
Here, S = [1, 2, 3, 4, …., 19, 20, 21, 22, 23, 24]
Let E = event of getting a multiple of 3 = [3, 6, 9, 12, 15, 18, 21, 24]
P (E) = n (E) / n (S) = 8 / 24 = 1/3
The answer is A.
Let E = event of getting a multiple of 3 = [3, 6, 9, 12, 15, 18, 21, 24]
P (E) = n (E) / n (S) = 8 / 24 = 1/3
The answer is A.