3 ltr of water is added with 11 ltr of a solution containing 42%of alcohol in the water.

3 ltr of water is added with 11 ltr of a solution containing 42%of alcohol in the water. The %of alcohol in the new mixture is?

Answer/Solution

33%

Steps/Work

We have a 11 litre solution containing 42% of alcohol in the water.
=> Quantity of alcohol in the solution
=11×42/ 100
Now 3 litre of water is added to the solution.
=> Total quantity of the new solution = 11 + 3 = 14
Percentage of alcohol in the new solution
=11×42/100
14
×
100
=11×4210014×100
=11×3/100
=33%
C

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ltr of water is added with ltr of a solution containing % of alcohol in the water. The % of alcohol in the new mixture is?

Calculated Answer

Step by Step Solution

In order to solve problem, you must evaluate (n₁ * n₂ / 100) / (n₀ + n₁) * 100.

n₀ =	3
n₁ =	11
n₂ =	42

(n₁ * n₂ / 100) / (n₀ + n₁) * 100
Evaluate n₂ / 100 = 0.42
(n₁ * 0.42) / (n₀ + n₁) * 100
Evaluate n₁ * 0.42 = 4.62
4.62 / (n₀ + n₁) * 100
Evaluate n₀ + n₁ = 14
4.62 / 14 * 100
Evaluate 4.62 / 14 = 0.33
0.33 * 100
Evaluate 0.33 * 100 = 33
33
The answer to the problem and the result of (n₁ * n₂ / 100) / (n₀ + n₁) * 100 is 33

Quiz

Answer/Solution

Steps/Work

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Calculated Answer

Step by Step Solution