A man is 18 years older than his son.
A man is 18 years older than his son. In eight years, his age will be twice the age of his son. The present age of this son is
Answer/Solution
10 years
Steps/Work
Explanation:
Let's Son age is x, then Father age is x+18.
=> 2(x+8) = (x+18+8)
=> 2x+16 = x+26
=> x = 10 years
Answer: Option B
Let's Son age is x, then Father age is x+18.
=> 2(x+8) = (x+18+8)
=> 2x+16 = x+26
=> x = 10 years
Answer: Option B