Two unbiased coins are tossed.
Two unbiased coins are tossed. What is probability of getting at most one tail ?
Answer/Solution
3/4
Steps/Work
Explanation:
Total 4 cases = [HH, TT, TH, HT]
Favourable cases = [HH, TH, HT]
Please note we need atmost one tail, not atleast one tail.
So probability = 3/4
Option D
Total 4 cases = [HH, TT, TH, HT]
Favourable cases = [HH, TH, HT]
Please note we need atmost one tail, not atleast one tail.
So probability = 3/4
Option D