if log 3 = 0.47712, the number of digits in 3128 is
if log 3 = 0.47712, the number of digits in 3128 is
Answer/Solution
62
Steps/Work
Explanation:
log(3128) = 128log(3) = 128 × 0.30103 ≈ 61.07
ie, its characteristic = 61
Hence, number of digits in 3128 = 61+1 = 62
Answer: Option E
log(3128) = 128log(3) = 128 × 0.30103 ≈ 61.07
ie, its characteristic = 61
Hence, number of digits in 3128 = 61+1 = 62
Answer: Option E