There are 5 bags three of which each contains 5 white and 2 black balls, and remaining 2 bags each ...
There are 5 bags three of which each contains 5 white and 2 black balls, and remaining 2 bags each contains 1 white and 4 black ball; a black ball has been drawn, find the chance that it came from second group.
Answer/Solution
28/43
Steps/Work
Please go through my solution and suggest any mistake.
Chances of selecting a black ball from group 1: 2/7----------------------Chances of selecting a black ball from group 2: 4/5
Thus combined probability of section of black ball from group 1:
3/5 x 2/7 = 6/35
Thus combined probability of section of black ball from group 2:
2/5 x 4/5 = 8/25
Out of these chances, chance of occurrence of first case : (8/25) / (6/35 + 8/25) = 28/43
D
Chances of selecting a black ball from group 1: 2/7----------------------Chances of selecting a black ball from group 2: 4/5
Thus combined probability of section of black ball from group 1:
3/5 x 2/7 = 6/35
Thus combined probability of section of black ball from group 2:
2/5 x 4/5 = 8/25
Out of these chances, chance of occurrence of first case : (8/25) / (6/35 + 8/25) = 28/43
D