What is the least value of integer N such that N!
What is the least value of integer N such that N! is divisible by 888 ?
Answer/Solution
37
Steps/Work
888 = 8*111 = 3*8*37
Hence 888 is a multiple of 37 and we need at least one 37 in N!
Therefore least value of N! is 37!, which will contain all of 3, 8, and 37.
Correct Option: D
Hence 888 is a multiple of 37 and we need at least one 37 in N!
Therefore least value of N! is 37!, which will contain all of 3, 8, and 37.
Correct Option: D