A fair coin with sides marked heads and tails is to be tossed eight times.
A fair coin with sides marked heads and tails is to be tossed eight times. What is the probability that the coin will land tails side up more than six times?
Answer/Solution
9/256
Steps/Work
More than 5 times tails = 7times+8times = 8C7 + 8C8 = 9
2 2 2 2 2 2 2 2
2^8 times total events and 9 events where tails side up .
So probability = 9/2^8 = 9/256 (Answer D)
2 2 2 2 2 2 2 2
2^8 times total events and 9 events where tails side up .
So probability = 9/2^8 = 9/256 (Answer D)