In 10 years, A will be twice as old as B was 10 years ago.

In 10 years, A will be twice as old as B was 10 years ago. If A is now 8 years older than B the present age of B is

Answer/Solution

38

Steps/Work

let present age of A be a and B be b
a+10 = 2*(b-10)
=> 2b-a = 30 ......(i)
a = b+8
=>2b-b-8 = 30
b=38
so the present age of b is 38 years
ANSWER:B

General Calculator / Auto Solver

In years, a will be twice as old as b was years ago. If a is now years older than b the present age of b is

Calculated Answer

38

Step by Step Solution

In order to solve problem, you must evaluate n₂ + n₀ + n₀ * 2.

n₀ =	10
n₁ =	10
n₂ =	8

n₂ + n₀ + n₀ * 2
Evaluate n₀ * 2 = 20
n₂ + n₀ + 20
Evaluate n₀ + 20 = 30
n₂ + 30
Evaluate n₂ + 30 = 38
38
The answer to the problem and the result of n₂ + n₀ + n₀ * 2 is 38