Two goods train each 500 m long, are running in opposite directions on parallel tracks.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answer/Solution
24 sec
Steps/Work
Relative speed =(45 + 30) km/hr
=(75 x(5/18)) m/sec
=(125/6) m/sec.
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
Therefore Required time = (500 x6/125)= 24 sec.
Answer :B
=(75 x(5/18)) m/sec
=(125/6) m/sec.
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
Therefore Required time = (500 x6/125)= 24 sec.
Answer :B