A number x is multiplied with itself and then added to the product of 4 and x.
A number x is multiplied with itself and then added to the product of 4 and x. If the result of these two operations is 12, what is the value of x?
Answer/Solution
2 and 6
Steps/Work
A number x is multiplied with itself --> X^2
added to the product of 4 and x --> X^2+4X
If the result of these two operations is -4 --> X^2+4X=4
i.e X^2+4X-12=0 is the Quadratic equation which needs to be solved.
(X-2)(X+6) = 0
Hence X=2, X=-6
IMO C
added to the product of 4 and x --> X^2+4X
If the result of these two operations is -4 --> X^2+4X=4
i.e X^2+4X-12=0 is the Quadratic equation which needs to be solved.
(X-2)(X+6) = 0
Hence X=2, X=-6
IMO C