Ages of two persons differ by 22 years.
Ages of two persons differ by 22 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
Answer/Solution
17,39
Steps/Work
Explanation:
Let the age of younger person is x,
Then elder person age is (x+22)
=> 3(x-6) = (x+22-6) [6 years before]
=> 3x-18 = x+16
=> x =17.
So other person age is x + 22 = 39
Answer: Option C
Let the age of younger person is x,
Then elder person age is (x+22)
=> 3(x-6) = (x+22-6) [6 years before]
=> 3x-18 = x+16
=> x =17.
So other person age is x + 22 = 39
Answer: Option C