A computer wholesaler sells six different computers and each is priced differently.
A computer wholesaler sells six different computers and each is priced differently. If the wholesaler chooses three computers for display at a trade show, what is the probability (all things being equal) that the two most expensive computers will be among the three chosen for display?
Answer/Solution
1/5
Steps/Work
Since, two of the choices are prefixed, we are free to choose 1 from the rest of the 4 avilable. so 4C1 is the numerator.
Total no of ways we can choose 3 from 6 is 6c3, which is the denominator.
So, the probability: 4c1/6c3= 1/5 ans is D.
Total no of ways we can choose 3 from 6 is 6c3, which is the denominator.
So, the probability: 4c1/6c3= 1/5 ans is D.