Jim is twice as old as Stephanie, who, four years ago, was three times as old as Kate.
Jim is twice as old as Stephanie, who, four years ago, was three times as old as Kate. If, five years from now, the sum Q of their ages will be 51, how old is Stephanie ?
Answer/Solution
10
Steps/Work
1) take C (14y.o.), so mean that S=14, J=28, their sum itself is 42+10 years from now is 52, it is over the 51,
so eliminate C,D,E
2) take B (10y.o.), Q=meaning S=10,J=20, so 20+10+10=40 and for K=10-4/3=2+9=11, finally 40+11=51. It is correct
B
so eliminate C,D,E
2) take B (10y.o.), Q=meaning S=10,J=20, so 20+10+10=40 and for K=10-4/3=2+9=11, finally 40+11=51. It is correct
B