If X is to be chosen at random from the integers between 1 to 6, inclusive, and Y is to be chosen at...
If X is to be chosen at random from the integers between 1 to 6, inclusive, and Y is to be chosen at random from the integers between 7 and 11, inclusive, what is the probability that X + Y will be even?
Answer/Solution
1/2
Steps/Work
X+Y will be even if X and Y are both even or both odd.
P(X and Y are both even) = 3/6*2/5 = 1/5
P(X and Y are both odd) = 3/6*3/5 = 3/10
P(X+Y is even) = 1/5 + 3/10 = 1/2
The answer is A.
P(X and Y are both even) = 3/6*2/5 = 1/5
P(X and Y are both odd) = 3/6*3/5 = 3/10
P(X+Y is even) = 1/5 + 3/10 = 1/2
The answer is A.