If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the ...
If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference W between the greatest and least of the five integers?
Answer/Solution
4
Steps/Work
(n-2 + n - 1 + n + n + 1 + n + 2)/5 = 2k - 1
=> n = 10k - 5
Greatest = n + 2 = 10k - 5 + 2 = 10k - 3
Least = n - 2 = 10k - 5 - 2
=> Difference W= 10k - 3 - (10k - 7)
= 4
Answer - D
=> n = 10k - 5
Greatest = n + 2 = 10k - 5 + 2 = 10k - 3
Least = n - 2 = 10k - 5 - 2
=> Difference W= 10k - 3 - (10k - 7)
= 4
Answer - D