A bowl of nuts is prepared for a party.

A bowl of nuts is prepared for a party. Brand P mixed nuts are 20% almonds and Brand Q's Deluxe nuts are 25% almonds. If a bowl contains a total of 68 ounces of nuts, representing a mixture of both brands, and 15 ounces of the mixture are almonds, how many ounces of Brand Q's Deluxe mixed nuts are used?

Quiz

Answer/Solution

28

Steps/Work

lets say x ounces of P is mixed with Q.
=> 68-x ounces of Q is present in the mixture (as the total = 68 ounces)
given total almond weight = 15 ounces
(20x/100)+(25/100)(68-x) = 15
=> x = 40
=> 68-40 = 28 ounces of Q is present in the mixture.
Answer is B.

General Calculator / Auto Solver

A bowl of nuts is prepared for a party. Brand p mixed nuts are % almonds and brand q's deluxe nuts are % almonds. If a bowl contains a total of ounces of nuts, representing a mixture of both brands, and ounces of the mixture are almonds, how many ounces of brand q's deluxe mixed nuts are used?

Calculated Answer

28

Step by Step Solution

In order to solve problem, you must evaluate (n3 - n2 * n0 / 100) / (n1 / 100 - n0 / 100).

n0 =20
n1 =25
n2 =68
n3 =15