The cost of registration at a professional association meeting was $50 per person; a lunch for ...
The cost of registration at a professional association meeting was $50 per person; a lunch for registrants only was available for an additional $22 per person. If the number of registrants who paid for lunch was 10 more than the number who did not, and if receipts for registration and lunch totaled $61720, how many people paid just for registration at the meeting?
Answer/Solution
500
Steps/Work
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Let the number of people who have opted only to register = x
Now since the registration cost is 50$ per person, the total amount sums to = 50x $
As per the information given in the question, the number of registrants who paid for lunch was 10 more than the number who did not. That means, total number of people who registered and paid for lunch = 10 + x.
For the people who registered for lunch the cost is 50 $ (for the event registration) + 22 $ (for lunch) = 72 $.
Total amount in this case sums to = 72(10 + x) = 720 + 72x
Now, total amount received was 61,720.
Thus, from the above data,
50x + 720 + 72x = 61720
122x = 61720 - 720
122x = 61000
x = 500.
Hence the correct Ans is D
Let the number of people who have opted only to register = x
Now since the registration cost is 50$ per person, the total amount sums to = 50x $
As per the information given in the question, the number of registrants who paid for lunch was 10 more than the number who did not. That means, total number of people who registered and paid for lunch = 10 + x.
For the people who registered for lunch the cost is 50 $ (for the event registration) + 22 $ (for lunch) = 72 $.
Total amount in this case sums to = 72(10 + x) = 720 + 72x
Now, total amount received was 61,720.
Thus, from the above data,
50x + 720 + 72x = 61720
122x = 61720 - 720
122x = 61000
x = 500.
Hence the correct Ans is D