Sum of the squares of three numbers is 314 and the sum of their products taken two at a time is 131....
Sum of the squares of three numbers is 314 and the sum of their products taken two at a time is 131. Find the sum?
Answer/Solution
24
Steps/Work
(a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 314 + 2* 131
a + b + c = √576 = 24
E
a + b + c = √576 = 24
E