A solution of 100 litres contains milk and water in the ratio 5:x.
A solution of 100 litres contains milk and water in the ratio 5:x. If ten litres of water is added to the solution, the ratio becomes 3:2, find the value of x?
Answer/Solution
2.57
Steps/Work
Exp. Total new quantity = original sol + water =100+10 =110
New ratio = 3:2, New quantity of milk =3/5*110 = 66 Lit,
New quantity of water = 2/5*110= 44 Lit
Water present initially = (44-10) = 34 Lit
Ratio = 66/34 =5/x There for x = 2.57
Answer: D
New ratio = 3:2, New quantity of milk =3/5*110 = 66 Lit,
New quantity of water = 2/5*110= 44 Lit
Water present initially = (44-10) = 34 Lit
Ratio = 66/34 =5/x There for x = 2.57
Answer: D