If (x/y)=(10/5), find the value (x^2+y^2)/(x^2-y^2)
If (x/y)=(10/5), find the value (x^2+y^2)/(x^2-y^2)
Answer/Solution
5/3
Steps/Work
= (x^2+y^2)/(x^2-y^2) = ( x^2 /y^2+ 1)/ ( x^2 /y^2-1) = [(10/5)^2+1] / [(10/5)^2-1]
= [(100/25)+1] / [(100/25)-1] = 5/3
Answer is A.
= [(100/25)+1] / [(100/25)-1] = 5/3
Answer is A.