A bowl was filled with 10 ounces of water, and 0.010 ounce of the water evaporated each day during a...
A bowl was filled with 10 ounces of water, and 0.010 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period?
Answer/Solution
5%
Steps/Work
Total amount of water evaporated each day during a 50-day period = .008 * 50
=.010 * 100/2
= 1.0/2
= .5
percent of the original amount of water evaporated during this period = (.5/10) * 100%
= 5 %
Answer D
=.010 * 100/2
= 1.0/2
= .5
percent of the original amount of water evaporated during this period = (.5/10) * 100%
= 5 %
Answer D