If x,y ,and z are positive real numbers such that x+y-z = 62, y-z+x =82 , and z-x+y = 100, then find...
If x,y ,and z are positive real numbers such that x+y-z = 62, y-z+x =82 , and z-x+y = 100, then find the x+y+z value?
Answer/Solution
82
Steps/Work
x+y-z = 62, ------1)
y-z+x =82 , ------2)
z-x+y = 100------3)
from (1)&(2)
2z=20
z=10
from (2)&(3)
2y = 182
y=91
then x=62-81= -19
x+y+z = 82
correct option is E
y-z+x =82 , ------2)
z-x+y = 100------3)
from (1)&(2)
2z=20
z=10
from (2)&(3)
2y = 182
y=91
then x=62-81= -19
x+y+z = 82
correct option is E