In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term.
In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 15th, 17th, and 18th terms in the sequence?
Answer/Solution
13(2^14)
Steps/Work
the sequence comes out to be 2^0,2^1,2^2,2^3 and so on...
so 15th term will be 2^14
17th term 2^16
18th term 2^17
adding all three
we get
2^14+(2^15)*4+(2^15)*8
so answer is 2^15(1+4+8)=>13(2^15)
answer D
so 15th term will be 2^14
17th term 2^16
18th term 2^17
adding all three
we get
2^14+(2^15)*4+(2^15)*8
so answer is 2^15(1+4+8)=>13(2^15)
answer D