The present ages of three persons are in proportions 4:7:9.
The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages?
Answer/Solution
16, 28, 36
Steps/Work
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
20x = 80 => x = 4
Their present ages are 16, 28 and 36 years respectively.Answer: B
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
20x = 80 => x = 4
Their present ages are 16, 28 and 36 years respectively.Answer: B