What is the smallest of six consecutive odd integers whose average (arithmetic mean) is b + 2?
What is the smallest of six consecutive odd integers whose average (arithmetic mean) is b + 2?
Answer/Solution
b -3
Steps/Work
Since the numbers are consecutive odd integers, mean = median = 3rd integer + 4th integer /2
And 1st integer= 3rd integer- 4
let's say 3rd integer = n and 4th integer = n+2
2n+2/2= b+2
n= b+1
1st integer= b+1-4= b-3
A is the answer
And 1st integer= 3rd integer- 4
let's say 3rd integer = n and 4th integer = n+2
2n+2/2= b+2
n= b+1
1st integer= b+1-4= b-3
A is the answer